## C# Shortest Superstring Problem Algorithms

Today, We want to share with you **C# Shortest Superstring Problem Algorithms**.

In this post we will show you **Shortest Superstring Problem in C#**, hear for *C# Program to find all substrings in a string* we will give you demo and example for implement.

In this post, we will learn about *Implementation of Shortest Common Supersequence Problem in C#* with an example.

### Shortest Superstring Problem

In this post, we will learn about **Shortest Superstring Problem** with an example.

Now in this post, I will explain **Shortest Superstring Problem** with appropriate example** in C#.Net**.For a given set of n strings myArr[], find the smallest string that contains each string in the given set as substring. Shortest Superstring Problem is a NP Hard problem. A solution which finds **shortest superstring** takes exponential time.

Here,Two strings are considered as overlapping if prefix of one string is same suffix of other string or vice verse. The vmaximum overlap mean length of the matching prefix and suffix is vmaximum.

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Input: myArr[] = {“geeks”, “quiz”, “for”}

Output: geeksquizfor

Input: myArr[] = {“catg”, “ctaagt”, “gcta”, “ttca”, “atgcatc”}

Output: gctaagttcatgcatc

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**Shortest Superstring Problem using C++**

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#include

#include

#include

#include

#include

using namespace std;

int findOverlappingPair(string s1, string s2, string& str)

{

int vmax = INT_MIN;

int m = s1.length();

int n = s2.length();

for (int i = 1; i <= min(m, n); i++)

{

if (s1.compare(m – i, i, s2, 0, i) == 0)

{

if (vmax < i)

{

//update vmax and str

vmax = i;

str = s1 + s2.substr(i);

}

}

}

for (int i = 1; i <= min(m, n); i++)

{

if (s1.compare(0, i, s2, n – i, i) == 0)

{

if (vmax < i)

{

vmax = i;

str = s2 + s1.substr(i);

}

}

}

return vmax;

}

string findShortestSuperstring(vector myArr)

{

int n = myArr.size();

while (n != 1)

{

int vmax = INT_MIN;

int p, q;

string res_str;

for (int i = 0; i < n; i++)

{

for (int j = i + 1; j < n; j++)

{

string str;

int r = findOverlappingPair(myArr[i], myArr[j], str);

if (vmax < r)

{

vmax = r;

res_str.assign(str);

p = i, q = j;

}

}

}

n–;

if (vmax == INT_MIN)

myArr[0] += myArr[n];

else

{

myArr[p] = res_str;

myArr[q] = myArr[n];

}

}

return myArr[0];

}

// Shortest Superstring Problem

int main()

{

vector myArr = { “CATGC”, “CTAAGT”, “GCTA”, “TTCA”, “ATGCATC” };

cout << "The Good Shortest Superstring is " << findShortestSuperstring(myArr);

return 0;

}

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